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3 years ago

I need help with this ignore the blank quiz

Mathematics

2 answers:

kari74 [83]3 years ago

8 0

3, two negatives equals a positive. so you could change both negatives to positives 18/6= 3

dsp733 years ago

6 0

The answer would be 3

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Circle O has a circumference of 132 feet. What is the approximate area of a circle O?

Archy [21]

Answer:1387.96

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Step-by-step explanation:

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3 years ago

Calculate the volume of the cylinder.Round your answer to the nearest hundredth 6cm height and 2cm width

Anvisha [2.4K]

Assuming width=diameter
diameter/2=radius

area=hpir^2

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3 years ago

Read 2 more answers

Help me pleasee !!!!

Daniel [21]

Answer:

here (edit I made a mistake)

Step-by-step explanation:

9) $y=\frac{3}{5} x +5$

10) y = x - 3

11) $y=-\frac{3}{5} x - 3$

12) $y=\frac{5}{4} x + 2$

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3 0

2 years ago

Read 2 more answers

2ln(4x –7) –1=11 Solve for x to the nearest 100th

ArbitrLikvidat [17]

2(4x - 7) -1 = 11
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8x - 15 = 11
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/8 /8
x = 3. 25 ------> Rounded: 3.30

3 0

4 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago