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Reika [66]
3 years ago
15

. A large bakery has many different products for sale. Suppose that 200 customers come in between 6 am and 10 am. Of the 200 cus

tomers, 140 order donuts, 100 order cinnamon rolls, and 80 order both. Suppose a customer is randomly selected:(d) If we know a person orders donuts, what is the probability that they order cinnamon rolls?
Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:\dfrac{4}{7}

Step-by-step explanation:

Formula for conditional probability:

P(B|A)=\dfrac{P(B\cap A)}{P(A)}

Given: n (donuts) = 140

n(donuts and cinnamon rolls) = 80

Now, the probability that they order cinnamon rolls given that we = know a person orders donuts  will be :

P(cinnamon\ rolls |\ donuts)=\dfrac{n(cinnamon\ and \ donuts)}{n(donuts)}\\\\=\dfrac{80}{140}\\\\=\dfrac{4}{7}

Required probability= \dfrac{4}{7}

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2 years ago
Number 18 pls help me
Harman [31]
Lila did it correctly. The answer is 324

Following PEMDAS, we first focus on the parenthesis. So we simplify 9-3 to get 6

So we go from 
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The next step is applying exponents. In this case, squaring the terms, so we go from
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Next is multiplying
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Finally, add up 288 and 36 to get 288+36 = 324

That confirms that Lila is correct

----------------------

The error that Rob made is that he computed 18*4^2+9^2-3^2 but it is NOT correct. Saying (x-y)^2 = x^2-y^2 isn't a true equation for all x and y. Again you have to simplify what is in the parenthesis first, and then you can square it. Or you must use the FOIL rule to expand out (9-3)^2


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