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Reika [66]
3 years ago
15

. A large bakery has many different products for sale. Suppose that 200 customers come in between 6 am and 10 am. Of the 200 cus

tomers, 140 order donuts, 100 order cinnamon rolls, and 80 order both. Suppose a customer is randomly selected:(d) If we know a person orders donuts, what is the probability that they order cinnamon rolls?
Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:\dfrac{4}{7}

Step-by-step explanation:

Formula for conditional probability:

P(B|A)=\dfrac{P(B\cap A)}{P(A)}

Given: n (donuts) = 140

n(donuts and cinnamon rolls) = 80

Now, the probability that they order cinnamon rolls given that we = know a person orders donuts  will be :

P(cinnamon\ rolls |\ donuts)=\dfrac{n(cinnamon\ and \ donuts)}{n(donuts)}\\\\=\dfrac{80}{140}\\\\=\dfrac{4}{7}

Required probability= \dfrac{4}{7}

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Evaluate - 6 – (-6) + 7 + (-4) + (-1).<br><br> What’s the answer please!!
elena55 [62]

Answer:

The answer is 2.

Step-by-step explanation:

Given: - 6 - (-6) + 7 + ( - 4) + ( - 1)

= - 6 + 6 + 7 - 4 - 1

= 6 + 7 - 6 - 4 - 1

= (6 + 7) - (6 + 4 + 1)

= 13 - 11

= 2

Hence, the answer.

4 0
3 years ago
Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs
Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}

AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

BC \approx 6.325

AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

7 0
3 years ago
Determine the slope of the line 3x − 5y − 6 = 0
igor_vitrenko [27]
<span>0=10, which is " never true" , and this leads to " no solution" also</span>
7 0
3 years ago
The answer is 2.95 (correct to 2 decimal places)
Ulleksa [173]

Answer:

2.947

2.946

2.948

2.949

2.945

Step-by-step explanation:

all decimal points are 5 or greater so you round up.

6 0
3 years ago
Find the line y=a+bx which best approximates the data points
Vika [28.1K]

Answer:

y = 11.84x - 32.71

Step-by-step explanation:

Here, the given data points,

(−3,−70),(−1,−42),(1,−21),(2,−9),(4,14),

Let x represents the input value and y represents the output value,

So, the table that represents the given situation is,

x         -3            -1             1             2             4

y       -70          -42         -21         -9             14

By the above table,

\sum x=3

\sum y=-128

\sum xy = 269

\sum x^2=31

\sum y^2 = 7382

Let the equation of the line is,

y = bx + a

Where,

a=\frac{\sum y \sum x^2 - \sum x\sum xy}{n(\sum x^2)-(sum x)^2}

b=\frac{n\sum xy - \sum x \sumy}{n(\sum x^2)-(\sum x)^2}

n = number of data points = 5,

By substituting the values we get,

a = - 32.70547945 ≈ - 32.71,

b = 11.84246575 ≈ 11.84,

Hence, the equation of line would be,

y = 11.84x - 32.71

8 0
3 years ago
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