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agasfer [191]
3 years ago
12

A company that makes hair-care products had 5,000 people try a new shampoo. Of the 5,000

Mathematics
1 answer:
Andru [333]3 years ago
8 0
1750 is 35 percent of 5000
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Solve the equations by factoring:<br><br>x^2−3x−40=0<br><br>4x^2−81=0
Alja [10]

Answer:

see explanation

Step-by-step explanation:

Given

x² - 3x - 40 = 0

Consider the factors of the constant term (- 40) which sum to give the coefficient of the x- term (- 3)

The factors are - 8 and + 5, since

- 8 × 5 = - 40 and - 8 + 5 = - 3, thus

(x - 8)(x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 8 = 0 ⇒ x = 8

x + 5 = 0 ⇒ x = 5

------------------------------------------------------

Given

4x² - 81 = 0 ← this is a difference of squares and factors in general as

a² - b² = (a + b)(a - b), thus

4x² - 81

=(2x)² - 9²

= (2x + 9)(2x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 9 = 0 ⇒ 2x = - 9 ⇒ x = - \frac{9}{2}

2x - 9 = 0 ⇒ 2x = 9 ⇒ x = \frac{9}{2}

8 0
3 years ago
Read 2 more answers
What is the solution to the equation 9 cubed x ≈ 7?
yulyashka [42]

<u>Answer</u>

7/729


<u>Explanation</u>

The question requires to you to find the value of x.

9³x = 7

729 x = 7

x = 7/729

4 0
3 years ago
For f(x)=1/x^2-3, find<br> a) f(3)<br> b) f(2+h)<br> Show/explain work
valentina_108 [34]

f(x)=\dfrac{1}{x^2-3}\\\\a)\ f(3)\to\text{put x=3 to the equation of the function f}\\\\f(3)=\dfrac{1}{3^2-3}=\dfrac{1}{9-3}=\dfrac{1}{6}\\\\Answer:\ \boxed{f(3)=\dfrac{1}{6}}\\\\b)\ f(2+h)\to\text{put x=2+h to the equation of a function f}\\\\f(2+h)=\dfrac{1}{(2+h)^2-3}\ \ \ |\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=\dfrac{1}{2^2+2(2)(h)+h^2-3}=\dfrac{1}{4+4h+h^2-3}=\dfrac{1}{h^2+4h+1}\\\\Answer:\ \boxed{f(2+h)=\dfrac{1}{h^2+4h+1}}

6 0
3 years ago
Math question, I appreciate ANY help! :)
pav-90 [236]
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8 0
3 years ago
Winston, a dog, loves to play fetch. He catches each ball mid-air independently with probability 0.4 (i.e. Bernoulli random vari
mafiozo [28]

Answer:

sorry i can, understantd

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3 years ago
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