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Brilliant_brown [7]
3 years ago
5

Tell me the ordered pair for the y-intercept.

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0
(0 , 3) is the ordered pair
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(4x+___)+(2x+3)=6x+5<br> Find the missing term.
SOVA2 [1]

Answer:

(4x+2)+(2x+3)=6x+5

Step-by-step explanation:

(4x+___)+(2x+3)=6x+5

4x+2x=6x

5-3=?

5-3=2

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3 years ago
If Nobody's Perfect, But Practice Makes Perfect. Why Practice?
Scilla [17]
To be the best you can be at whatever you're practicing. Just because you can't be perfect doesn't mean you can't be very good at it.
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4 years ago
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Nicholas sprints the length of a football field. If a football field measures 100 yards and 1 yard is approximately 0.914 meter,
KatRina [158]

Answer:

91.4 meters

Step-by-step explanation:

From the question:

1 yard = 0.914 meter

100 yards = x meters

x meter = 100 × 0.914 meters

x = 91.4 meters

Therefore, Nicholas sprinted 91.4 meters

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3 years ago
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Which is equivalent to 256 Superscript three-fourths? 4 12 64 192
Vaselesa [24]

Answer: 64

Step-by-step explanation:

256 is thesame thing as 2 raise to power of 8.

We then multiply 2 raise to power 8 by the power of 3/4. We will then be left with 2 raise to power 6.

2 raise to power 6 equals:

= 2 × 2 × 2 × 2 × 2 × 2

= 64

Check the attached file for proper explanation.

7 0
4 years ago
On the way to work Juan carpools with a fellow co-worker then takes the city bus back home in the evening. The average speed of
podryga [215]

Answer:

\frac{40r+100}{r(r+5)}

Step-by-step explanation:

Let r represent speed in the carpool.

We have been given that on the way to work Juan carpools with a fellow co-worker then takes the city bus back home in the evening. The average speed of the 20-mile trip is 5 miles per hour faster in the carpool.

We know that time is equal to distance over speed.

The total distance is 20 mile. Time taken to travel 20 miles using carpool would be \frac{20}{r}

The speed on the bus is 5 miles greater, so it will be x+5. Time taken to travel 20 miles using bus would be \frac{20}{r+5}

Total time will be equal to sum of both times that is:

\frac{20}{r+5}+\frac{20}{r}

Let us simplify our expression.

\frac{20r}{r(r+5)}+\frac{20(r+5)}{r(r+5)}

\frac{20r}{r(r+5)}+\frac{20r+100}{r(r+5)}

Combine numerator:

\frac{20r+20r+100}{r(r+5)}

\frac{40r+100}{r(r+5)}

Therefore, our required expression would be \frac{40r+100}{r(r+5)}.

7 0
3 years ago
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