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prohojiy [21]
3 years ago
14

What is the name of the big hole in the ground in Northern Arizona

Computers and Technology
2 answers:
kotegsom [21]3 years ago
3 0

Answer:

is that sink hole, I think it is

aliya0001 [1]3 years ago
3 0
I believe the answer would be the Grand Canyon. Hope this helps :)
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Carol typed a memo to send to everyone in her department. To create this memo, she used a _____.
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she used a word processor

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If a printer can print 10 characters per second how many minutes (rounded) would it take to print a page with 66 lines of 80 cha
maks197457 [2]

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8.8 Minutes

Explanation:

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3 years ago
Consider two different implementations of the same instruction set architecture. The instructions can be divided into four class
patriot [66]

Answer:

Processor P_2 is faster than P_1.

Part A:

For Processor P_1:

CPI=2.6

For Processor P_2:

CPI=2

Part B:

For Processor P_1:

CPU CLOCK CYClE=2.6*10^{6}

For Processor P_2:

CPU CLOCK CYClE=2*10^{6}

Explanation:

We will find the instructions executed of each class:

For Class A=1*10^{6} *10%=1*10^{5}

For Class B=1*10^{6} *20%=2*10^{5}

For Class C=1*10^{6} *50%=5*10^{5}

For Class D=1*10^{6} *20%=2*10^{5}

CPU CLOCK CYClE=\sum_{n=1}^{i}*CPI_i*C_i

Where:

C_i is the instructions of each class (Calculated above)

For Processor P_1:

CPU CLOCK CYClE=(1*1*10^{5})+ (2*2*10^{5})+ (3*5*10^{5})+ (3*2*10^{5})

CPU CLOCK CYClE=2.6*10^{6}

For Processor P_2:

CPU CLOCK CYClE=(2*1*10^{5})+ (2*2*10^{5})+ (2*5*10^{5})+ (2*2*10^{5})

CPU CLOCK CYClE=2*10^{6}

Now:

CPU TIME=CPU CLOCK CYClE/CYCLE RATE

For Processor P_1:

CPU TIME=\frac{2.6*10^{6} }{2.5*GHz} =1.04ms

For Processor P_2:

CPU TIME=\frac{2*10^{6} }{3*GHz} =666.67ms

Processor P_2 is faster than P_1.

Part A:

CPI=CPU CLOCK CYClE/Number of instructions

For Processor P_1:

CPI=\frac{2.6*10^{6}}{1*10^{6}}=2.6

For Processor P_2:

CPI=\frac{2*10^{6}}{1*10^{6}}=2

Part B:

For Processor P_1:

CPU CLOCK CYClE=(1*1*10^{5})+ (2*2*10^{5})+ (3*5*10^{5})+ (3*2*10^{5})

CPU CLOCK CYClE=2.6*10^{6}

For Processor P_2:

CPU CLOCK CYClE=(2*1*10^{5})+ (2*2*10^{5})+ (2*5*10^{5})+ (2*2*10^{5})

CPU CLOCK CYClE=2*10^{6}

4 0
3 years ago
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