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viva [34]
3 years ago
12

Write the equation of a direct variation that passes through the point (-11, 13)

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0
<h2>Answer:</h2>

<u>A direct variation equation is of the form y = m⋅x for some constant value m</u>.

<u>For a direct variation equation passing through</u>

(x,y) = (-11,13)

13 = m × - 11

→ m = - 13/11.

so, as y = m⋅x

y = - 13/11x

<u>Hence, the direct variation equation is [C] - 13/11x</u>.

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Simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2} is \mathbf{\frac{1}{(x+3)(x+4)} }

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Step-by-step explanation:

We need to find simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}

Solving the given expression:

\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}

First we find factors of x^2+x-6

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So, simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2} is \mathbf{\frac{1}{(x+3)(x+4)} }

Option A is correct answer.

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