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lesya [120]
3 years ago
11

**Need to get this all done** Evaluate functions from their graph g(3)=??

Mathematics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

4

Step-by-step explanation:

g(x) is the graph. g(3) is where the graph has a value of 3 for x.

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How do I find a percent out f three numbers that are not percents
drek231 [11]
"Turn the two numbers into a fraction; place the number you want to turn into a percentage over the whole value. Convert the fraction into a decimal. Multiply the decimal by 100 to get the percent."
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3 years ago
A sixth- grade math teacher can grade 25 homework assignments in 20 minutes. Is he working at a faster rate or slower rate than
Akimi4 [234]

Answer:

  faster

Step-by-step explanation:

25 in 20 minutes is 25/20 = 1.25 per minute

36 in 30 minutes is 36/30 = 1.20 per minute

The first rate is faster.

5 0
3 years ago
Hurry I need it ASAP!
zhuklara [117]
 If I calculated correctly, I believe the answer is B
3 0
3 years ago
An SRS of 25 recent birth records at the local hospital was selected. In the sample, the average birth weight was x = 119.6 ounc
Evgen [1.6K]

Answer:

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X}= \mu = 119.6

And now for the deviation we have this:

SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3

So then the correct answer for this caee would be:

c. 1.30 ounces.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X}= \mu = 119.6

And now for the deviation we have this:

SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3

So then the correct answer for this caee would be:

c. 1.30 ounces.

6 0
3 years ago
The length of time it takes to get through the security checks at a very large urban airport is a random variable with mean μ =
gregori [183]
A) The population and sample mean are always the same ... in this case, it is 20.6 minutes. 

<span>b) First convert the data to z-values: </span>

<span>P(X<18) = P(z < (18-20.6)/8.4) = P(z< -0.3095) </span>

<span>Now, using a Standard Normal table, look up z= -0.3095 </span>

<span>P(X<18) = 0.3785 </span>

<span>Hope that helps</span>
8 0
3 years ago
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