Answer:
616 yd³
Step-by-step explanation:
Volume = base × height
The volume of the prism
= (7×8) ×11
= 616 yd³
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Answer:
All the properties of a rhombus apply (the ones that matter here are parallel sides, diagonals are perpendicular bisectors of each other, and diagonals bisect the angles). All the properties of a rectangle apply (the only one that matters here is diagonals are congruent). All sides are congruent by definition.
Answer:
m∠QTR = 98°
Step-by-step explanation:
From the picture attached,
Radii of the circle are TQ and TR measuring equal lengths.
Therefore, ΔTQR is a isosceles triangle.
Opposite angles of the equal sides will be equal in measure.
m∠RQT = m∠TRQ = 41°
By angle sum theorem,
m∠RQT + m∠TRQ + m∠QTR = 180°
41° + 41° + m∠QTR = 180°
m∠QTR = 180° - 82°
= 98°
Therefore, m∠QTR = 98°
The answer for this question will be 30
