Answer:
Rises to the left and rises to the right.
Step-by-step explanation:
Since, the given function is f(x)=
, and the end behavior of the given function is determined as:
Consider the given function f(x)=, identify the degree of the function:
The degree of the function is : 4 which is even
And then identify the leading coefficient of the given function that is +2 which is positive in nature.
Hence, the function is positive and even in nature, therefore, the end behavior of the function will be rising to the left and rising to the right.
We know that
g=3
r=2
b=5
total marbies=g+r+b------> 3+2+5----> 10
a) <span>probability that the first marble is red
P(red)=r/total marbies------------> 2/10-----> 1/5
b) </span><span>probability that the second marble is blue
in this case total marbles-------> 9
P(blue)=b/total marbles----------> 5/9
c) </span><span>the probability that the first marble is red and the second is blue
(1/5)*(5/9)=1/9
the answer is
1/9</span>
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
cot(x)sec⁴(x) cot(x)sec⁴(x)
0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
0 = cos⁴(x)(1 + tan²(x))²
0 = cos⁴(x) or 0 = (1 + tan²(x))²
⁴√0 = ⁴√cos⁴(x) or √0 = (√1 + tan²(x))²
0 = cos(x) or 0 = 1 + tan²(x)
cos⁻¹(0) = cos⁻¹(cos(x)) or -1 = tan²(x)
90 = x or √-1 = √tan²(x)
i = tan(x)
(No Solution)
2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
sin²(x) - cos²(x) = sin²(x) - cos²(x)
+ cos²(x) + cos²(x)
sin²(x) = sin²(x)
- sin²(x) - sin²(x)
0 = 0
3. 1 + sec²(x)sin²(x) = sec²(x)
sec²(x) sec²(x)
cos²(x) + sin²(x) = 1
cos²(x) = 1 - sin²(x)
√cos²(x) = √(1 - sin²(x))
cos(x) = √(1 - sin²(x))
cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
x = 0
4. -tan²(x) + sec²(x) = 1
-1 -1
tan²(x) - sec²(x) = -1
tan²(x) = -1 + sec²
√tan²(x) = √(-1 + sec²(x))
tan(x) = √(-1 + sec²(x))
tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
x = 0
Answer:
choice 4 (or D)
Step-by-step explanation:
1) the initial argument (x/2) and the final one (x) shows horizontal compression of the given function;
2) the different between (-1) and (-5) is (-4); it means shifting down 4 units;
3) the correct answer is: t<u>he graph is compressed horizontally by a factor 2 and shifted down 4 units</u>.
Answer:
10/15 = 2/3
Story:
Mia had 15 cupcakes out on 5 tables her friends ate 2/3s of every table, What fraction does this represent and what is it simplified.
