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Alinara [238K]
3 years ago
14

This is for my friend so if you could solve this asap that would be great

Mathematics
2 answers:
Yuliya22 [10]3 years ago
8 0

Answer:

1. 5x^2 − 3x − 2

2. 4s^2 −28s + 49

3. 4y^2 + 9y + 8

musickatia [10]3 years ago
8 0

Answer:

<h2><u>[1] 5x² - 3x - 2</u></h2><h2><u>[2] 4s² - 28s + 49</u></h2><h2><u>[3] 4y² + 9y + 8</u></h2>

Explanation:

  • (3x² + 4) - (-2x² + 3x + 6)

<u>Remove Parenthesis: (a) = a</u>

3x² + 4 - (-2x² + 3x + 6)

<u>Simplify -(-2x² + 3x + 6): 2x² - 3x - 6</u>

3x² + 4 + 2x² - 3x - 6

<u>Simplify 3x² + 4 + 2x² - 3x - 6</u>

5x² - 3x - 2

  • (2s - 7)²

<u>Apply Perfect Square Formula: (a - b)² = a² - 2ab + b²²: a = 2s, b = 7</u>

(2s)² - 2 · 2s · 7 + 7²

<u>Simplify (2s)² - 2 · 2s · 7 + 7²</u>

4s² - 28s + 49

  • (7y² + 9y - 2) + (-3y² + 10)

<u>Remove Parenthesis: (a) = a</u>

7y² + 9y - 2 - 3y² + 10

<u>Group Like Terms</u>

7y² - 3y² + 9y - 2 + 10

<u>Add Similar Elements: 7y² - 3y² = 4y²</u>

4y² + 9y - 2 + 10

<u>Add: -2 + 10 = 8</u>

4y² + 9y + 8

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F(x) = x ^ 2 - 8x + 7
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Answer:
They have the same x-value
f(x) has the greater minimum
Step-by-step explanation:
To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:
x = -b / 2a
Remember that a second degree equation has the following form:
ax^2 + bx + c
so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation
x = - (-8) / 2(1)
x = 8 / 2
x = 4
This means that the two functions have the same x-value.
The y value of f(x) would be
f(4) = (4)^2 - 8(4) + 7
f(4) = 16 - 32 + 7
f(4) = -9
So the vertex, or minimun value of f(x) would be at the point (4, -9).
The vertex, or minimun value of g(x) is at the point (4, -4).
So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
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