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kogti [31]
3 years ago
5

Brittany bought a dress that cost $22.50. If the sales tax is 6.5%, how much tax did she pay? PLZZ ITS TIMED

Mathematics
2 answers:
Ann [662]3 years ago
6 0

I'm pretty sure the answer's $1.46.

($1.46 is the amount of tax, not the total)

<em>Hope this helped, please mark brainiest! </em>

anastassius [24]3 years ago
3 0

Start with your $22.50 subtotal (cost without tax)

Then, solve for 6.5% of $22.50

Set your equation up like so: 6.5/100=x/22.50

Cross multiply then you should have 100x=146.25

Solve to get 1.4625% (If you need it rounded, it's 1.5%)

1.5% ----> $1.46

$22.50+$1.56=$23.96

She spent $23.96

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Lilit [14]
"SAS" is how you find the angle in between. Use the law of cosines to calculate the unknown side, then use the law of sines to find the simuliar of the other two angles, then use three angles add to 180 degrees to find the last angle.
3 0
3 years ago
Prove that the value of the expression: (5^18–25^8)(16^4–2^13–4^5) is divisible by 30 and 44.
makvit [3.9K]

The value of the expression is not divisible by 30 and 44.

<u>Explanation:</u>

(5^1^8 - 25^8) (16^4-2^1^3-4^5)\\=(5^1^8 - 5^2^\times^8) (2^4^\times^4 - 2^1^3 - 2^2^\times^5)\\=(5^1^8 - 5^1^6)(2^1^6-2^1^3-2^1^0)\\=(5^2) ( 2^3-2^1^0)\\=(25) (8-1024)\\=(25) \times (-1016)\\= -25400

To check the number -25400 be divisible by 30 and 44, divide the number -25400 by 30 and 44

On dividing -25400 by 30 we get, -846.66

On dividing -25400 by 44 we get, -577.27

Therefore,

The value of the expression is not divisible by 30 and 44.

6 0
4 years ago
The number of siblings an individual has varies from student to student. The distribution of the number of siblings is strongly
ivanzaharov [21]

Answer:

(e) the mean number of siblings for a large number of students has a distribution that is close to Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

By the Central Limit Theorem

The sampling distributions with a large number of students(at least 30) will be approximately normal, so the correct answer is given by option e.

7 0
3 years ago
Examine this system of equations. Which number can be multiplied by each equation so that when the two equations are
andreyandreev [35.5K]

Answer:

15 times the first equation and -12 times the second equation

Step-by-step explanation:

we have

\frac{3}{4}x+\frac{2}{3}y=6 ------> first equation

\frac{5}{8}x+\frac{5}{6}y=12 ------> second equation

Multiply the first equation by 15 both sides

(15)\frac{3}{4}x+(15)\frac{2}{3}y=6(15)

\frac{45}{4}x+10y=90 -----> new first equation

Multiply the second equation by -12 both sides

(-12)\frac{5}{8}x+(-12)\frac{5}{6}y=12(-12)

-\frac{60}{8}x-10y=-144 -----> new second equation

Adds the two new equations

\frac{45}{4}x+10y=90\\-\frac{60}{8}x-10y=-144\\-----------\\\frac{45}{4}x-\frac{60}{8}x=90-144

The y-term was eliminated

5 0
3 years ago
Please help :( i’m struggling
neonofarm [45]

Answer:33

Step-by-step explanation:

Add all sides

6 0
3 years ago
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