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inn [45]
3 years ago
9

Please help :) it's not to hard​

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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The composite figures below are made of right prisms.
Arada [10]

Answer:

nFigure 3 has the largest surface area thats all i know

all i Step-by-step explanation:

8 0
3 years ago
Which rule describes the translation PQR --> P'Q'R'?
Ksenya-84 [330]
The "Pre Image" is the image that we started with, so the pink triangle. 
The "Image" is the image that we ended with, so the blue triangle. 

To determine how far we went from the pre image to the image, we can focus on one point, let's say point "P". 

The pre image coordinates for point "P" are 2, 3. 
The image coordinates for point "P'" are -1, 0. 

To get from x value 2 to x value -3, we subtracted 3. 
To get from y value 3 to y value 0, we subtracted 3. 

So, our rule for this translation would be A, (x, y) ----> (x-3, y-3).
5 0
3 years ago
PLEASE HELP!!!! The total yield of rice in a farm is 10^8 kg, and the land is10^5 km. What is the output of rice every km? (the
Margaret [11]

Answer:

10^3 kg

Step-by-step explanation:

Think about it that you have the total yield 10^8 kg of rice from 10^5 km^2 of land. You now only want How much does 1 km^2 of land produce. Which can be shown as

10^8/10^5=??/1. To get the denominator to equal one you divide the top and bottom of the first problem by 10^5. 10^8/10^5 is 10^3. So it's 10^3 kg

6 0
3 years ago
Read 2 more answers
Rose is making greeting cards, which she will sell by the box at an arts fair. She paid $50 for a booth at the fair, and the mat
dusya [7]

Answer:multiply

Step-by-step explanation:6x4 but i aint sure tho

5 0
3 years ago
Heeeeeeeeeeeeelpppppppppppppppp!
Alexus [3.1K]
To figure out which of the coordinates don't work, we need to substitute their values of x and y to figure out if they work or not. We will know they don't work if the result we get is something crazy like 2=25. 

Substitute the values of x and y from a
\left \{ {{5 (6) = 3(5) +15 } \atop {6(5)=10(6)-30}} \right.

Now we simplify
\left \{ {{30 = 30 } \atop {30=30} \right. 
Since this is true we know that the point (5,6) works. Now let's move onto B. 

Once again, we substitute. 
\left \{ {{5 (12) = 3(-15) +15 } \atop {6(-15)=10(12)-30}} \right.

This simplifies to 
\left \{ {{60=-30} \atop {-90=90} \right.
Since this is obviously not right, we know that is the point that doesn't work in this system of equations. 
5 0
4 years ago
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