At university A, 46% of the undergraduate students are female. At university B, 52% of the undergraduate students are female. Su
ppose a random sample of 100 students from both schools was selected. Assume the sampling distribution of p hat Subscript Upper A Baseline minus p hat Subscript Upper B is approximately Normal. What is the probability that the proportion of females selected from university A is greater than the proportion of females selected from university B?
If needed, use the z-table to answer the question.
Step-by-step explanation: Any line parallel to 2x+3y+11=0 is the form 2x+3y =k this can also be written as x/(k/2)+y/k/3 =1 this is the line whose sum of the intercepts is 15, then k/2 +k/3 = 15 after solving we get that indeedk= 18.
