Answer: The ramp would be 15.5 feet long.
Step-by-step explanation: Please refer to the attached diagram for details.
Angle C shows the angle to be formed by the ramp from the ground, which is 15 degrees. Also, from the ground, it’s going to be four feet tall, which is line AB. The top of the ramp is point A, which makes line AC the entire length of the ramp. Since we have a reference angle (angle C) and two sides, the opposite and the hypotenuse, we shall apply the trigonometric ratio.
SinC = opposite/hypotenuse
Sin 15 = 4/b
By cross multiplication we now have
b = 4/Sin15
b = 4/0.2588
b = 15.4599
Approximately b = 15.5
Therefore the length of the ramp would be 15.5 feet
Answer:
Step-by-step explanation:
1/2 * 2.5
= 1.25 seconds
Answer:
3.8 seconds
Step-by-step explanation:
Given equation

When the ball hits the ground then height is 0
So we replace h with 0 and solve for t

a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t

=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)



Now make two fractions and solve for x
t=
=-0.0815
t=
=3.83
So answer is 3.8 seconds
:) There's no picture but I can solve this for you :)
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