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sleet_krkn [62]
3 years ago
14

Solve for x. A) 6 B) 9 C) 15 D) 18

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

whats the equation.......

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Write the algebraic expression for the difference between the squares of two numbers.
V125BC [204]

The algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is

a² - b² = (a + b)(a - b).

An algebraic expression is a combination of terms, where the terms are separated using mathematical operators like plus (+), minus (-), multiply (*), and divide (/).

The terms are combinations of numerals and variables.

Variables are represented alphanumerically, which can hold any value as per the expression they are used in.

In the question, we are asked to write the algebraic expression for the difference between the squares of two numbers.

We assume the two numbers to be a and b respectively.

Thus, we are asked to write an expression for the difference between the square of a and square of b, that is, we are asked to write an expression for a² - b².

We know that a² - b² is an identity, which can be shown as (a + b)(a - b).

Thus, the algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is a² - b² = (a + b)(a - b).

Learn more about algebraic expressions at

brainly.com/question/2241589

#SPJ4

6 0
2 years ago
Money of Rp. 24,000.00 can buy 3 kg of apples. If Anto buys apples with money
ss7ja [257]

Answer:

5 Kg of apples

Step-by-step explanation:

cost of apples per kg = 24000.00/3

=8000.00

amount of apples bought = 40000.00/8000.00

=5 Kg

He got 5kg of apples with Rp.40,000.00

8 0
2 years ago
When 4(0.5x+2.5y-0.7x-1.3y+4) is simplified, what is the resulting expression?
padilas [110]

Answer:

-0.8x + 4.8y + 16

Step-by-step explanation:

4(0.5x+2.5y-0.7x-1.3y+4) = 4( 0.5x - 0.7x  + 2.5y - 1.3y + 4)

= 4( -0.2x  + 1.2y + 4)

= 4*(-0.2x)  + 4 *1.2y + 4*4

= -0.8x + 4.8y + 16

8 0
3 years ago
Read 2 more answers
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
4 years ago
(sorry bout the other one I forgot to put the picture and it wouldn't let me delete)
Sergio039 [100]
I’m pretty sure it is.
8 0
3 years ago
Read 2 more answers
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