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pashok25 [27]
3 years ago
5

Find the discriminant to determine the number of solutions for the quadratic equation a^2-5a=6

Mathematics
1 answer:
Bingel [31]3 years ago
3 0
A^2-5a = 6
a^2-5a-6 = 0
Discriminant = (-5)^2-4(1)(-6) = 49
Discriminant is positive so there are two solutions
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A clothing store donated a percent of every sale to hospitals. The total sales were $7,750 so the
Flauer [41]

Answer:

4%

Step-by-step explanation:

310 /7759 x 100% = 4%

6 0
3 years ago
Maddy has a bag of 36 marbles. The probability of picking green is 1 in 2, the probability of picking red is 1 in 3, and the pro
KonstantinChe [14]

Answer:  1 in 18

This is the same as writing the fraction 1/18

==============================================================

Explanation:

Since she has 36 marbles total, and the probability of picking green is 1 in 2, this means (1/2)*36 = 18 marbles are green.

Then she also has (1/3)*36 = 12 red marbles and (1/9)*36 = 4 blue marbles.

So far, that accounts for 18+12+4 = 34 marbles in all. That leaves 36-4 = 2 marbles left over that must be black, as it's the only color left.

From that, the probability of choosing a black marble is 2/36 = 1/18.

There's a 1 in 18 chance of Maddy picking a black marble.

1/18 = 0.0556 = 5.56% approximately

7 0
3 years ago
12.5% of a number is 25, find the number
tankabanditka [31]

Answer:

200

Step-by-step explanation:

Let's call the number x :
12.5% of x = 25

Changing 12.5% into decimal would be 0.125

Now we have the equation :

0.125x = 25

Divide both sides by 0.125 to make x the subject :

x = 25 ÷ 0.125

x = 200

To check we can substitute this value into the question :

12.5% of 200 = 25

Hope this helped and have a good day

4 0
2 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
Solve the system
Helga [31]
The answer is actually choice A

---------------------------------------------------------
---------------------------------------------------------

If we add up the equations straight down we will have 0a+2b = 6

Note how adding the 'a' terms gives us 3a + (-3a) = 3a-3a = 0a. The 0a term is really 0 since 0 times anything is 0. So the 'a' terms will go away

The equation 0a+2b = 6 turns into 0+2b = 6 and that simplifies to 2b = 6

To isolate b, we divide both sides by 2

2b = 6
2b/2 = 6/2
b = 3

We can stop here since only one answer choice has b = 3, which is choice A. However, let's keep going to find the value of 'a'

Plug b = 3 into any equation with 'a' and 'b', then solve for 'a'

3a+4b = 9
3a+4*3 = 9
3a+12 = 9
3a+12-12 = 9-12
3a = -3
3a/3 = -3/3
a = -1

So a = -1 and b = 3 pair up to form (a,b) = (-1,3)

--------------------------------------

To check, plug this ordered pair back into both equations

Equation 1:
3a+4b = 9
3*(-1)+4*3 = 9
-3+12 = 9
9 = 9
Equation 1 has been checked out

Equation 2:
-3a-2b = -3
-3(-1)-2(3) = -3
3 - 6 = -3
-3 = -3
this is true as well

So this confirms that the final answer is choice A
8 0
3 years ago
Read 2 more answers
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