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sergeinik [125]
3 years ago
12

Use vector notation to describe the points that lie in the given configuration. (Let s and t be elements of the Reals.)

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

Step-by-step explanation:

Given the data in the question;

A vector is in the span of V1 and V2 only if it is a linear combination.

of V1 and V2.

so 'V' is in the span if;

V = SV1 + tV2 [ S and t are real numbers ]

V =    [ 6si + 5sj ] + [ 6tj + 5tz]

V = 6s, 5s+6t, 5t

so

I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

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What is the additive inverse of x+3 ​
andre [41]

Answer:

-x-3

Step-by-step explanation:

(x+3) + the additive inverse = 0

the additive inverse = -(x+3)

7 0
3 years ago
Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy
Margaret [11]

Answer:

Part 1) The exact solutions are

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})   and  (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

y=x^{2} +3x ----> equation A

y=2x+5 ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +x-5=0  

so

a=1\\b=1\\c=-5

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}

x=\frac{-1\pm\sqrt{21}} {2}

so

The solutions are

x_1=\frac{-1+\sqrt{21}} {2}

x_2=\frac{-1-\sqrt{21}} {2}

<em>Find the values of y</em>

<em>First solution</em>

For x_1=\frac{-1+\sqrt{21}} {2}

y=2(\frac{-1+\sqrt{21}} {2})+5

y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}

The first solution is the point (\frac{-1+\sqrt{21}} {2},4+\sqrt{21})

<em>Second solution</em>

For x_2=\frac{-1-\sqrt{21}} {2}

y=2(\frac{-1-\sqrt{21}} {2})+5

y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}

The second solution is the point (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Round to the nearest hundredth

<em>First solution </em>

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21}) -----> (1.79,8.58)

(\frac{-1-\sqrt{21}} {2},4-\sqrt{21}) -----> (-2.79,-0.58)

see the attached figure to better understand the problem

6 0
4 years ago
3 .912+s=5.313 evaluate
taurus [48]

Answer:

s= 1.401

Subtract 5.313 from 3.912 :D

3 0
3 years ago
A sprinter runs 100 meters in 11.5 seconds. What is the runners average rate in meters per second?
iris [78.8K]

Answer:

8.69565217391 m per sec

8.7 (1dp)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Josh And ash order 2 whole pizzas to eat.Josh ate 5/8 slices of pizza and ash ate 6/8 slices of pizza.Who much pizza is still le
Elenna [48]

2-5/8-6/8=16/8-5/8-6/8=5/8 pizza slices left

3/8+7/8=10/8=1 2/8 pizza slices altogether

hope it helps:))

8 0
3 years ago
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