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tresset_1 [31]
2 years ago
13

Need help somebody help me

Mathematics
1 answer:
Whitepunk [10]2 years ago
7 0

Answer:

question?

Step-by-step explanation:

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circle a has a radius of 7 and arcs rc cs and sm are congruent to the nearest hundereth what is the length of arc rc
oksian1 [2.3K]
The complete question in the attached figure

we know that
[arcs rc +arc cs arc sm]---------------> they take up half a circle-------->180°
<span> they are all congruent
so
divide 180 by 3 ----------------> 180/3=60</span>°


Find the length of arc rc=60°<span>

if 360</span>°----------------> (2*pi*7) length of circumference 
60° -------------------> X
<span>X=60*2*pi*7/360------------> 7.327 units

the answer is
</span>the length of arc rc= <span>7.33 units

</span>

3 0
3 years ago
Mr. Indigo purchased some trees to plant in his backyard. He bought three oak trees for $23 each and an elm tree for $42. What w
Rom4ik [11]

Answer:

Total cost = $111

Step-by-step explanation:

Given:

Total number of oak tree = 3

Total number of elm tree = 1

Each oak tree cost = $23

Each elm tree cost = $42

Find:

Total cost

Computation:

Total cost = 3[Each oak tree cost] + 1[Each elm tree cost]

Total cost = 3[23] + 1[42]

Total cost = 69 + 42

Total cost = $111

4 0
3 years ago
Please help!!! it will mean alot :/
ASHA 777 [7]

Answer:

Answwe is 44

Step-by-step explanation:

that the answer

8 0
2 years ago
Read 2 more answers
Pls awnser this question I will give brainliest pls
Makovka662 [10]

Answer:

My guess is G

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
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