<span>Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2).
If Saturn’s orbital period is 29.5 years, then
29.5 = a^(3/2)
a = (29.5)^(2/3) = 9.547
Therefore, Saturn's distance from the sun is 9.547 astronomical units.</span>
I used 3.14 for pi to solve easier.
6. 6.28
7. 21.98
8. 94.2
Answer:
27y + 18z
Step-by-step explanation:
9(3y+2z)
Distribute the 9
9 * 3y + 9* 2z
27y + 18z
Answer:6
Step-by-step explanation:
