I will give u all my brainly points which is 71

I need help on this homework question please

zheka24 [161]

(a) In functional notation, you are asked for C(600).

For this, put 600 where t is in the functional notation C(t).

(b) The value multiplying 8 is 0.5 when the exponent of 0.5 is 1. That is

... t/5730 = 1

Multiplying by 5730 gives

... t = 5730

It will take 5730 years for half the Carbon 14 to be gone.

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Or, you can recognize a fraction is 1 when its numerator is the same as its denominator. That is t/5730 = 5730/5730 = 1 when t=5730.

3 0

3 years ago

Mrs. Lopez is designing her garden in the shape of a rectangle. The area of her garden is 2 times greater than the area of the r

scoray [572]

To find the expression for the area of the rectangular garden we will find the area of the rectangle in the picture and then double it.

Area of the garden will be represented by the expression 32s⁵ ft².

Mrs. Lopez is designing her rectangular garden which is 2 times greater than the area of the rectangle shown in the picture.

Dimensions of the rectangle in the picture are 4s³t ft and 8s² ft.

Therefore, area of the rectangle in the picture = Length × Width

= 4s³t × 8s²

= 32s⁵t ft²

Since, area of the garden is 2 times greater than the area of the rectangle given in the picture.

Therefore, area of the garden = 2(area of the rectangle given in the garden)

= 2(32s⁵t) square feet.

= 64s⁵t square feet

Learn more,

brainly.com/question/17419256

6 0

3 years ago

(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.

DaniilM [7]

Answer:

The answer is " $\frac{2}{9} \ and \ \frac{1}{9}$ "

Step-by-step explanation:

In point a:

The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They can pick 1 Chunin form of the matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They have the option to pick 1 join from of the country team with such a probability: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

And we can make the country teams: $3! = 6$ different forms. Its chances of choosing a team full in the process described also are:

$6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.$

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

Its odds of choosing the same rank ninja in such a different country team are: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

The likelihood of choosing the same level Ninja from the residual matter of national is: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$ Therefore, all 3 selected ninjas are likely the same grade: $3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$