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marissa [1.9K]
3 years ago
5

Is 10\3 a improper fraction? Explain

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

Answer: Yes

Step-by-step explanation:

An improper fraction is any fraction that has a numerator that is greater than the denominator

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-2/3 ÷2 4/1 ​=<br> what is the answer i need help
Dominik [7]

Answer: Exact Form:

−19

Decimal Form:

−0.¯1

Step-by-step explanation:

8 0
3 years ago
There are twenty trays of paint. Each tray has five colors. One of the colors is purple. What fraction of the colors is purple i
suter [353]
In one tray, we have 1/5. Since one is purple out of the 5 colors. 

So in 20 trays, we have:

(1/5) x 20 = 20/5 = 4
6 0
3 years ago
Read 2 more answers
What is the value of m,the points (2,3),(3,6)and (m,12) are collinear....Please y'all help me out
timurjin [86]

Answer:

m = 5

Step-by-step explanation:

Since the points are collinear, they all lie on the same line and have the same slope between them.

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (3, 6)

m = \frac{6-3}{3-2} = \frac{3}{1} = 3

Now calculate the slope using 2 other points and equate to 3

(x₁, y₁ ) = (3,  6) and (x₂, y₂ ) = (m, 12)

m = \frac{12-6}{m-3} = \frac{6}{m-3} = 3 ( multiply both sides by m - 3 )

6 = 3(m - 3) ← divide both sides by 3

2 = m - 3 ( add 3 to both sides )

5 = m

4 0
3 years ago
Read 2 more answers
At which values of x does the function F(x) have a vertical asymptote? Check all that apply.
Anton [14]

You get vertical asymptotes because the x-value causes you to try to divide by 0.  

If you look at the denominator, the x-values of 0, 1, and -5 all will make the denominator equal to 0, making the whole function explode.  

    You find these by solving  3x(x-1)(x+5)=0.

That's your answer: 0, 1, and -5

3 0
3 years ago
Identify at least one Hamilton path and at least one Hamilton circuit
Anna71 [15]

We will investigate how to determine Hamilton paths and circuits

Hamilton path: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex can be different.

Hamilton circuit: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex must be the same!

As the starting point we can choose any of the points. We will choose point ( F ) and trace a path as follows:

F\to D\to E\to C\to A\to B\to F

The above path covers all the vertices/points with the starting and ending point/vertex to be ( F ). Such a path is called a Hamilton circuit per definition.

We will choose a different point now. Lets choose ( E ) as our starting point and trace the path as follows:

E\to D\to F\to B\to A->C

The above path covers all the vertices/points with the starting and ending point/vertex are different with be ( E ) and ( C ), respectively. Such a path is called a Hamilton path per definition.

One more thing to note is that all Hamilton circuits can be converted into a Hamilton path like follows:

F\to D\to E\to C\to A\to B

The above path is a hamilton path that can be formed from the Hamilton circuit example.

But its not necessary for all Hamilton paths to form a Hamilton circuit! Unfortunately, this is not the case in the network given. Every point is in a closed loop i.e there is no loose end/vertex that is not connected by any other vertex.

4 0
1 year ago
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