Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Mathematics

2 answers:

inessss [21]3 years ago

5 0

Answer:

(a). <em>y = 3x - 11 ;</em> (b). <em>y = </em> $-\frac{1}{3}$ <em> x - 1 </em>

Step-by-step explanation:

Parallel lines have the same slopes

Slopes of perpendicular lines are opposite reciprocals.

(3, - 2)

The slope of given line is 3

<em>(a)</em>. Equation of ║ line is

y + 2 = 3(x - 3)

<em>y = 3x - 11</em>

<em>(b).</em> Slope of perpendicular line is $-\frac{1}{3}$

y + 2 = $-\frac{1}{3}$ (x - 3)

<em>y = </em> $-\frac{1}{3}$ <em> x - 1</em>

AlladinOne [14]3 years ago

5 0

Answer:

A. y=3x-11

B. y=-1/3x-1

Step-by-step explanation:

I know my maths

You might be interested in

Daniel guesses that he scored a 95 on his science test.His actual score is 91. What is the percent error in Daniel's guess? Roun

Kamila [148]

1) Formula for the percent of error:

                               [estimated measure - real measure]
Percent of error = ---------------------------------------------------- x 100
                                            real measure

2) Calculations:

                             [95 - 91]
Percent error = --------------- x 100 = 4.4 %
                                 91

Answer: 4.4%

3 0

3 years ago

You have a fishing line spool with an end that has an area of 20.0 cm2. How much fishing line do you need to wind around the spo

lana66690 [7]

<h3>Problem Solution</h3>

Assuming the spool is a cylinder and the circumference we're winding around is that of a circle with the given area, we can write the relation between circumference and area as

... C = 2√(πA)

10 times the circumference is then

... 10C = 20√(π·20 cm²) = 40√(5π) cm ≈ 159 cm

<h3>Formula Derivation</h3>

The usual formulas for circumference and area are

... C = 2πr

... A = πr²

If we multiply the area formula by π and take the square root, we get

... πA = (πr)²

... √(πA) = πr

Multiplying this by 2 gives circumference.

... C = 2√(πA) = 2πr