Which situation has the lowest cost per can?

Draw the dilation of ABCD using center D and scale factor 1/3. Label the dilation EFGH

kati45 [8]

Answer:

Please find attached, the required drawing of quadrilateral ABCD and the dilation of quadrilateral ABCD scaled down by a scale factor of 1/3

Step-by-step explanation:

The coordinates of the quadrilateral ABCD are;

A(0, 6), B(6, 6), C(9, 0), D(0, 0)

From the dilation by a scale factor of 1/3, using D as the center of dilation, we have from the attached drawing, the following coordinates of the quadrilateral EFGH as E(0, 2), F(2, 2), G(3, 0) H(0, 0) which is the quadrilateral ABCD scaled down by 1/3

4 0

2 years ago

What is the value of 3 + 1 when n = 4?<br> 13<br> 7<br> 8<br> 12

Marrrta [24]

Answer:

13

Step-by-step explanation:

3n=12+1=13

6 0

3 years ago

Which property is shown? 2.3 + (-1.2 + 9.6) = (2.3+ (-1.2)) + 9.6

abruzzese [7]

Answer:

Associative property of addition

Step-by-step explanation:

A change of grouping is the associative property of addition.

6 0

3 years ago

Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard devia

jeyben [28]

Answer:

The range is 77.

The variance is 739.8.

The standard deviation is 27.2.

Step-by-step explanation:

The data provided, in ascending order is as follows:

S = {11 , 14 , 23 , 31 , 40 , 60 , 63 , 68 , 75 , 77 , 88}

The range of a data set is the difference between the maximum and minimum values.

From the above data set we know,

Maximum = 88

Minimum = 11

Compute the range as follows:

Range = Maximum - Minimum

= 88 - 11

= 77

The range is 77.

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x_{i}=\frac{1}{11}\times [11+14+23+...+88]=50$

Compute the variance as follows:

$\sigma^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}$

$=\frac{1}{11-1}\times [(11-50)^{2}+(14-50)^{2}+...+(88-50)^{2}]\\\\=\frac{1}{10}\times 7398\\\\=739.8$

The variance is 739.8.

Compute the standard deviation as follows:

$\sigma=\sqrt{\frac{1}{n-1}\sum (x_{i}-\bar x})^{2}}=\sqrt{739.8}=27.199265\approx 27.2$

The standard deviation is 27.2.

4 0

3 years ago

Which function in vertex form is equivalent to f(x) = x2 + x +1? f(x) = (x + one-quarter) squared + three-quarters f(x) = (x + o

a_sh-v [17]

The function in vertex form is $f(x)=(x+\frac{1}{2})^{2}+\frac{3}{4}$ ⇒ 3rd answer

Step-by-step explanation:

The vertex form of the quadratic function f(x) = ax² + bx + c is

f(x) = a(x - h)² + k, where

a is the coefficient of x²
(h , k) are the coordinates of the vertex point
$h=\frac{-b}{2a}$ , wher b is the coefficient of x
k = f(h), that means value f(x) when x = h

∵ f(x) = x² + x + 1

∴ a = 1 , b = 1

∵ $h=\frac{-b}{2a}$

- Substitute the values of a and b to find h

∴ $h=\frac{-1}{2(1)}$

∴ $h=\frac{-1}{2}$

Substitute the value of x in f(x) by the value of h to find k

∵ f( $\frac{-1}{2}$ ) = $(\frac{-1}{2})^{2}+\frac{-1}{2}+1$

∴ f( $\frac{-1}{2}$ ) = $\frac{1}{4}-\frac{1}{2}+1$

∴ f( $\frac{-1}{2}$ ) = $\frac{3}{4}$

- k is the value of f(x) when x = h

∵ h = $\frac{-1}{2}$

∴ k = f( $\frac{-1}{2}$ )

∴ k = $\frac{3}{4}$

Substitute the values of a, h and k in the vertex form

∵ f(x) = a(x - h)² + k

∵ a = 1 , $h=\frac{-1}{2}$ , $k=\frac{3}{4}$

∴ $f(x)=1(x-\frac{-1}{2})^{2}+\frac{3}{4}$

∴ $f(x)=(x+\frac{1}{2})^{2}+\frac{3}{4}$

The function in vertex form is $f(x)=(x+\frac{1}{2})^{2}+\frac{3}{4}$

Learn more:

You can learn more about the quadratic functions in brainly.com/question/9390381

#LearnwithBrainly

7 0

3 years ago

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