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Lostsunrise [7]
3 years ago
6

Can u guys make a story with this graph good luck this is velocity ​

Mathematics
1 answer:
enot [183]3 years ago
8 0
Yeahh I could do it
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Solve for the variable: 12.9 = x + 7.1 5.8 -5.8 20 -20
olya-2409 [2.1K]
12.9 = x + 7.1
subtract 7.1 from both sides to isolate the variable, x.

5.8 = x

5.8 is your answer.
3 0
3 years ago
A sedan will drive ten miles north, 15 miles east, 13 miles south, 15 miles west, and 22 miles
pishuonlain [190]
The total distance is 75 miles
4 0
3 years ago
A grocery store stocks different flavors of peppermint sticks in 15 jars. The number of sticks in each jar varies from 0 to 49.
Iteru [2.4K]

Answer:

The correct answers are:

A. The Vertical axis should be labelled as the Number of Jars for Each Flavour

B. an interval of 7 could be appropriate

Step-by-step explanation:

A. The number of jars for each flavour is the dependent variable against the flavour type, which is the independent variable, hence it is displayed on the vertical axis to show the height of the bars.

B. since the number of sticks in a jar vary from 0 to 49, dividing 49 by 7 will give 7 without a remainder, hence, an interval of 7 will be ideal for the plot, nd a total of 7 bars will be plotted. Intervals are: 0-7, 8-14, 15-21, 22-28, 29-35, 36-42, 43-49.

3 0
3 years ago
2/3x+4=2x true or false
aleksley [76]

Answer: False !!!

do the math

5 0
3 years ago
Help me with the work
Tpy6a [65]

Answer:

Option B k > 0

Step-by-step explanation:

we know that

Observing the graph

The slope of the line is positive

The y-intercept is negative

we have

3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)

The slope of the line is equal to

m=\frac{1}{3}[5k+2]

Remember that the slope must be positive

so

5k+2> 0\\ \\k > -\frac{2}{5}

The value of k is greater than -2/5

Analyze the y-intercept

(2-\frac{4}{3}k) < 0\\ \\ 2 < \frac{4}{3}k\\ \\1.5 < k\\ \\k > 1.5

1.5 is greater than zero

so

the solution for k is the interval ------> (1.5,∞)

therefore

must be true

k > 0

5 0
3 years ago
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