Answer:
20π ft³
Step-by-step explanation:
I just did it on the USATestprep
Answer:
- slant height: 6 units
- lateral area: 108 square units
Step-by-step explanation:
<u>Given</u>
A right regular hexagonal pyramid with ...
- base side length 6 units
- base apothem 3√3 units
- height 3 units
<u>Find</u>
- lateral face slant height
- pyramid lateral surface area
<u>Solution</u>
a) The apothem (a) and height (b) of the pyramid are two legs of the right triangle having the slant height as its hypotenuse (c). The Pythagorean theorem tells us the relationship is ...
c = √(a² +b²) = √((3√3)² +3²) = √(27+9) = √36
c = 6
The slant height of the pyramid is 6 units.
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b) The lateral surface area of the pyramid is the area of each triangular face, multiplied by the number of faces. The area of one face will be ...
A = (1/2)bh = (1/2)(6 units)(6 units) = 18 units²
Then the lateral surface area is 6 times this value:
SA = 6(18 units²) = 108 units²
The lateral surface area of the pyramid is 108 square units.
Answer:
9/20 = 0.45
3/10 = 0.3
7/12 = 0.5833333
4/5 = 0.8
2/3 = 0.66667
5/6 = 1.6667
1/6 = 0.16667
15/16 = 0.9375
2/15 = 0.13333
4/11 = 0.3636
5/8 = 0.625
13 / 16 = 0.8125
3/25 = 0.12
4/9 = 0.4444
8/9 = 0.88889
11/16 = 0.6895
14 / 25 = 0.56
11/15 = 0.7333
Step-by-step explanation:
9/20 = 0.45
3/10 = 0.3
7/12 = 0.5833333
4/5 = 0.8
2/3 = 0.66667
5/6 = 1.6667
1/6 = 0.16667
15/16 = 0.9375
2/15 = 0.13333
4/11 = 0.3636
5/8 = 0.625
13 / 16 = 0.8125
3/25 = 0.12
4/9 = 0.4444
8/9 = 0.88889
11/16 = 0.6895
14 / 25 = 0.56
11/15 = 0.7333
