Answer:
55.56%
Step-by-step explanation:
= (20 / 36) × 100
= 0.56 × 100
= 55.56%
Answer:
5
Step-by-step explanation:
Answer:nsnsjsjsksnsnsnns
Step-by-step explanation:
Answer:
Auxiliary pump should be started at 6:36 PM
Step-by-step explanation:
Let the volume of oil tanker be V.
An oil tanker can be emptied by the main pump in 5 hours,
![\texttt{Rate of main pump = }\frac{V}{5}](https://tex.z-dn.net/?f=%5Ctexttt%7BRate%20of%20main%20pump%20%3D%20%7D%5Cfrac%7BV%7D%7B5%7D)
An auxiliary pump can empty the tanker in 12 hours,
![\texttt{Rate of auxiliary pump = }\frac{V}{12}](https://tex.z-dn.net/?f=%5Ctexttt%7BRate%20of%20auxiliary%20pump%20%3D%20%7D%5Cfrac%7BV%7D%7B12%7D)
We need to find when should the auxiliary pump be started so that the tanker is emptied by 9 PM if the main pump is started at 5 PM.
Difference in times = 4 hours
That is main pump works for 4 hours and let auxiliary pump works for t hours.
We have
![\frac{V}{5}\times 4+\frac{V}{12}\times t=V\\\\t=12\times \left ( 1-\frac{4}{5}\right )=12\times \frac{1}{5}=2.4hours](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7B5%7D%5Ctimes%204%2B%5Cfrac%7BV%7D%7B12%7D%5Ctimes%20t%3DV%5C%5C%5C%5Ct%3D12%5Ctimes%20%5Cleft%20%28%201-%5Cfrac%7B4%7D%7B5%7D%5Cright%20%29%3D12%5Ctimes%20%5Cfrac%7B1%7D%7B5%7D%3D2.4hours)
So auxiliary pump works for 2.4 hours,
It should be started at 9 - 2.4 = 6.6 PM = 6:36 PM
Auxiliary pump should be started at 6:36 PM
Answer:the answer will be D.
Step-by-step explanation:
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