11. m=5 p=15
12. g=3 k=3
13. b=40
Answer:
3/4, 3:4, 3 to 4
Step-by-step explanation:
The equation representing the cost of the ride is R = $5 + $0.45dd.
<h3>What is flat fee? </h3>
The flat fee charged is the fixed cost. This cost remains constant regardless of the distance travelled. The additional fee is the variable cost. It increases with the distance travelled.
<h3> Derivation of the equation that represents cost of the ride.</h3>
Total cost = fixed cost + (variable cost x miles driven)
R = $5 + $0.45dd
To learn more about flat fees, please check: brainly.com/question/25879561
6a + 5 + x + 7x - 2a
Combine like terms.
4a + 5 + 6x
Answer:
No, mn is not even if m and n are odd.
If m and n are odd, then mn is odd as well.
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Proof:
If m is odd, then it is in the form m = 2p+1, where p is some integer.
So if p = 0, then m = 1. If p = 1, then m = 3, and so on.
Similarly, if n is odd then n = 2q+1 for some integer q.
Multiply out m and n using the distribution rule
m*n = (2p+1)*(2q+1)
m*n = 2p(2q+1) + 1(2q+1)
m*n = 4pq+2p+2q+1
m*n = 2( 2pq+p+q) + 1
m*n = 2r + 1
note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.
The result 2r+1 is some other odd number as it fits the form 2*(integer)+1
Therefore, multiplying any two odd numbers will result in some other odd number.
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Examples:
- 3*5 = 15
- 7*9 = 63
- 11*15 = 165
- 9*3 = 27
So there is no way to have m*n be even if both m and n are odd.
The general rules are as follows
- odd * odd = odd
- even * odd = even
- even * even = even
The proof of the other two cases would follow a similar line of reasoning as shown above.
