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2 years ago

Can u make sure I'm correct and help me with the last 3?

Mathematics

2 answers:

GuDViN [60]2 years ago

8 0

7x2=14 2x7=14

5x3=15 3x5=15

6x1/4 = 1/5 1/4x6=1/5

12x2/3=8 2/3x12=8

10x1/2=5 1/2x10=5

2/3x1/5=2/15 1/5x2/3=2/15

1/2x1/3=1/6 1/3x1/2=1/6

Ray Of Light [21]2 years ago

7 0

1/2 times 10 is 10/2 but it reduces to 5. Last ones are 2/15 and 1/6

You might be interested in

V<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2A%202%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4} * 2

myrzilka [38]

Answer:

$1\frac{3}{4}$

Step-by-step explanation:

In order to find the answer, you first need to convert the mixed number (2 1/3) into a improper fraction and then multiply.

$\frac{3}{4} \times2\frac{1}{3}$

$2\frac{1}{3} =3\times2=6+1=7=\frac{7}{3}$

$\frac{3}{4} \times\frac{7}{3}$

$3\times7=21$

$4\times3=12$

$=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}$

$=1\frac{3}{4}$

Hope this helps.

7 0

2 years ago

Complete the steps to find the value of x.<br> 2x<br> 1289<br> 22<br> 2

Oksanka [162]

Answer:

Step-by-step explanation:

2x = 128

x = 128/2

x = 64

6 0

2 years ago

Y= -x +3 and y = x - 1

inysia [295]

Answer:

x=2 and y=1

Step-by-step explanation:

Rewrite equations:

y=−x+3;y=x−1

Step: Solve

y=−x+3

Step: Substitute−x+3foryiny=x−1:

y=x−1

−x+3=x−1

−x+3+−x=x−1+−x(Add -x to both sides)

−2x+3=−1

−2x+3+−3=−1+−3(Add -3 to both sides)

−2x=−4−2x−2=−4−2

(Divide both sides by -2)

x=2

Step: Substitute2forxiny=−x+3:

y=−x+3

y=−2+3

y=1(Simplify both sides of the equation)

Hope this Helps you :)

3 0

2 years ago

Which congruence theorem can be used to prove △ABC ≅ △DBC?

Tema [17]

Answer:

SAS

Step-by-step explanation:

Hope this helps :)

7 0

2 years ago

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

3 0

2 years ago