Solve for x:
-3 (3 x + 15) - (x + 10) = 35
-3 (3 x + 15) = -9 x - 45:
-9 x - 45 - (x + 10) = 35
-(x + 10) = -x - 10:
-9 x + -x - 10 - 45 = 35
Grouping like terms, -x - 9 x - 45 - 10 = (-9 x - x) + (-45 - 10):
(-9 x - x) + (-45 - 10) = 35
-9 x - x = -10 x:
-10 x + (-45 - 10) = 35
-45 - 10 = -55:
-55 - 10 x = 35
Add 55 to both sides:
(55 - 55) - 10 x = 55 + 35
55 - 55 = 0:
-10 x = 35 + 55
35 + 55 = 90:
-10 x = 90
Divide both sides of -10 x = 90 by -10:
(-10 x)/(-10) = 90/(-10)
(-10)/(-10) = 1:
x = 90/(-10)
The gcd of 90 and -10 is 10, so 90/(-10) = (10×9)/(10 (-1)) = 10/10×9/(-1) = 9/(-1):
x = 9/(-1)
Multiply numerator and denominator of 9/(-1) by -1:
Answer: x = -9
8 and 3/10 because the 3 is in the ones place so you make that a fraction which would be 3/10. Then 8 would be a whole number. Hope this helps!
Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
The equation perpendicular to the line passing through the points (-4,7) and (1,3) is
<h3>Equation perpendicular to a line</h3>
The slope of the given line is calculated as:
The equation perpendicular to the given line will be of the form
Substitute 
Therefore, the equation perpendicular to the line passing through the points (-4,7) and (1,3) is
Learn more on perpendicular equations here: brainly.com/question/1441594
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