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Ronch [10]
3 years ago
7

Just say here to answer correctly if you want 100 points

Spanish
1 answer:
dimulka [17.4K]3 years ago
4 0
I am here, but my answer has to be 20 things long
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Simplify x^3-125/2x-10
MAVERICK [17]
We \ first, \ simplify \  \frac{125}{2} \\ \\   \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\  pulling \ out \ like \ factors : \\ \\  2x^3 - 125x  =   x * (2x^2 - 125) \\ \\ Factoring: \  2x^2 - 125

<span>Here's how!</span>

Proof :  \ (A+B) * (A-B) =\\&#10;         A2 - AB + BA - B2 =\\&#10;         A2 - AB + AB - B2 = \\&#10;         A2 - B2\\

<span>Therefore</span> . . . 

\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }

<span>The factors would then be the following:</span>

→ ( Leading \  Coefficient :  1,2)
→ (Trailing Constant) :  1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }} <span>✔</span>
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