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Taya2010 [7]
2 years ago
6

CAN SOMEONE HELPPPP!!!!

Mathematics
2 answers:
andrey2020 [161]2 years ago
8 0

Answer: z = 8

Step-by-step explanation: z-6 take away 5 - 12 and you get 8

Nesterboy [21]2 years ago
5 0

Answer:

z=10

10-5z=-4z

10=-4z+5z

10=z

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Which best explains if quadrilateral WXYZ can be a parallelogram?
nekit [7.7K]

A quadrilateral in which opposite sides are parallel is called a parallelogram. The correct option is A.

<h3>What is a parallelogram?</h3>

A quadrilateral in which opposite sides are parallel is called a parallelogram. Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

For a parallelogram, the pair of opposite sides are equal and parallel. Therefore,

1.)  For the first pair.

(x+8) = 15

x = 7

2.) For the second pair

(x+2)=(2x-5)

x + 2 = 2x - 5

2 + 5 = 2x - x

x = 7

(x+2) = (7+2) = 9

Since the measure of the pair of opposite sides is 15 units, the pair of the other two sides measure 9 units.

Hence, the correct option is A.

The complete question is mentioned in the below image.

Learn more about Parallelogram:

brainly.com/question/1563728

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7 0
2 years ago
2x – 2 7 <br> how do i graph this?
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8 0
3 years ago
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A rental car company charges $15/day for a rental car plus 20¢ for every mile driven that day. Which equation models the relatio
nikdorinn [45]
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3 years ago
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Len [333]

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5 0
2 years ago
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If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
2 years ago
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