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klio [65]
3 years ago
14

The voltage, V, in an electric circuit is held constant, the current I, is inversely proportional to the resistance, R. If the c

urrent is 120mA (milliampere) when resistance is 5 ohms, find the current when the ersistance is 15 ohms.​
Mathematics
1 answer:
erica [24]3 years ago
4 0

Answer:

70 amps

Step-by-step explanation:

The current I is inversely proportional to the resistance R

I=k/R   (k is the constant of proportionality)

A)   I=210 amperes

     R=4 ohms

I=k/R

k=I×R

k=210×4=840

B)    R=12 ohms

     k=840

    I=k/R

   I=840/12=70 amperes

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a bowler knocks down at least 6 pins 70% of the time. Out of 200 rolls, how many times can you predict the bowler will not down
Naddik [55]
Since he knocks at least 6 pins 70% of the time.

For 200 rolls:

70% of 200

= (70/100) * 200

= (7/10) * 200

= 140

140 times. 

hope this helps :)
5 0
4 years ago
Which of the following phrases are equations? Choose 2 answers:
Ksivusya [100]

Answer:

the answers are Band C

Step-by-step explanation:

B. using the number line n greater than -8

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4 0
3 years ago
The area of a circle of radius 10 units is equal to the surface area of a sphere of radius 5 units.
Hoochie [10]
<h3>Answer:  True</h3>

Explanation:

The area of the circle with radius 10 is...

A = pi*r^2

A = pi*10^2

A = 100pi

The surface area of the sphere with radius 5 is...

SA = 4pi*r^2

SA = 4pi*5^2

SA = 100pi

Both results are the same, so the claim is true. We can think of surface area as the amount of wrapping paper needed to cover the sphere.

6 0
2 years ago
EFG is an isosceles triangle in E such that EF = EG = 6cm and FG = 5cm. The circle (C) with center O and diameter [EG] intersect
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Answer:

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8 0
3 years ago
Can someone pls help me with diagram 2 I'm confused about how I'm supposed to find the number for the corners like the other two
olga_2 [115]
Isn't that interesting? What a neat little problem.

The middle number between a and b = (a + b)/2
The middle number between b and c = (b + c) / 2
The middle number between c and d = (c + d)/2
The middle number between d and a = (d + a)/2

The sum of the numbers in the corners of
diagram 1 =  a + b + c + d Do you agree.

Now look at diagram two. Start by putting a, b, c and d in the corners.
Now remove the brackets from what I found above.
diagram 2 = a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2 + a/2 Now collect all the like terms.
<em>diagram 2 = a/2 + a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2</em>
<em>a/2 + a/2 = a does it not?</em>
<em>b/2 + b/2 = b</em>
<em>c/2 + c/2 = c</em>
<em>d/2 + d/2 = d</em>

<em>The sum of the middle numbers in diagram 2 = a + b + c + d</em>
<em>But that's the same sum as diagram 1, which was what you were asked to prove. </em>You cannot come up with a counter example that will give a different result, at least in the positive integers.

The question provides you with room for a written answer. You are going to have to reproduce in some form what I've put in italics.

Thank you for posting.
6 0
3 years ago
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