PLS HELP

lorasvet [3.4K]

Answer:

87.0454545455

Step-by-step explanation: This is hard to explain on this text box. Please go to this https://www.wikihow.com/Do-Long-Division. Remember, always put a decimal point at the end. If you run out of number and you have a number left over. Keep adding zeros to the dividend.

7 0

4 years ago

It takes Peter 4 hours to walk 12 miles.If he continues to walk at the same rate, how long will it take him to walk:

blondinia [14]

Answer:

a]2.3 hrs

b]3.6hrs

Step-by-step explanation:

4hrs = 12 miles

x = 7miles

4 x 7=28/12=2.3

4 x 11=44/12=3.6hrs

6 0

4 years ago

Read 2 more answers

The sum of two numbers is 72. The difference of the two numbers is 40. What are the two numbers.

Oxana [17]

Step-by-step explanation:

x + y = 72

x - y = 40

x = y + 40

so, the first equation is then

y + 40 + y = 72

2y + 40 = 72

2y = 32

y = 16

x = y + 40 = 16 + 40 = 56

7 0

1 year ago

Abner receives a toy catalog in the mail.The catalog has 25 pages and shows 11 toys on each page.Abner wants to know what is the

weqwewe [10]

The answer is 275 because when you multiply 11 by 25 you get 275

5 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago