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bonufazy [111]
3 years ago
10

GEOMETRY. Name a Pair of Parallel AND PERPENDICULAR lines.

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer:

I'm certain that it's AB and HI

Step-by-step explanation:

Crazy boy [7]3 years ago
6 0

Answer: Parallel: AB and HI

Perpendicular: GE and AE

Step-by-step explanation:

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7(x-3)+6=5x-9 please solve the equation fully
TiliK225 [7]

Answer:

I love algebra anyways

The ans is x=3 steps is in the picture with the ans

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

4 0
3 years ago
-6x+6y=42<br> help me big test question
BabaBlast [244]
X= (-7,0)
Y= (0,7)
This is for graphing I hope that’s what your test is about.
6 0
3 years ago
Which number is a reasonable estimate for the sum of the equation 1,267 + 3,894 = ________? 5,000 6,000 7,000 8,000
just olya [345]

Answer:

5,000

Step-by-step explanation:

1,267 + 3,894 = 5161

7 0
3 years ago
Read 2 more answers
HELP!!!!! part A: Ms.Donaldson earns $18.80 per hour for the first 40 hours she works in a week. She earns 1 1/2 times that amou
Elena-2011 [213]

Answer: A. $907.10

B. $628.236

Step-by-step explanation:

For the first 40 hours, Ms.Donaldson will earn: = 40 × $18.80 = $752.0

We are informed that Ms.Donaldson worked 45.5 hours, this means that she worked an extra 5.5 hours. The amount paid for the extra hour will be:

= 5.5 × 1.5 × 18.8

= $155.10

The amount she earned will be:

= $752.0 + $155.10

= $907.10

B. A health incurrence payment of $34.55 was deducted from Ms.Donaldson's earnings for the week. Therefore, the amount she will have after the deduction will be:

= $907.10 - $34.55

= $872.55

After the incurrence deduction, payroll taxes equal to 28% of the balance were deducted. What was the amount that Ms.Donaldson received afterwards?

This will be:

= $872.55 - (28% × $872.55)

= $872.55 - (0.28 × $872.55)

= $872.55 - $244.314

= $628.236

7 0
3 years ago
I really need help with this i beg you !!
sweet-ann [11.9K]

Answer:

The perimeter and area of the square are 56 units and 196 square units, respectively.

Step-by-step explanation:

The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is \sqrt{2} time the length of any of its legs. If the hypotenuse has a measure of 7\sqrt{2}, then the legs of the triangle have a measure of 7.

Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.

Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:

Perimeter

p = 4\cdot l (1)

Area

A = l^{2} (2)

Where l is the side length of the square.

If we know that l = 14, then the perimeter and area of the square are, respectively:

p = 4\cdot (14)

p = 56

A = 14^{2}

A = 196

The perimeter and area of the square are 56 units and 196 square units, respectively.

7 0
3 years ago
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