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puteri [66]
2 years ago
11

What is the are of the polygon? А D 9 cm E 9 cm 5 cm C 12 cm B

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
5 0
I think the answer is a e
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Enter the number in sdentific notation. 86,257 = Hint: Move the decimal left 4 places.​
marin [14]

Answer:

8.6257*10^4

Step-by-step explanation:

move the decimal left 4 places

multiply 10^however many decimal places you moved

boom

6 0
3 years ago
Write an expression that is equivalent to 30(x + y + 1)
Lerok [7]

Answer:

30x + 30y +30

Step-by-step explanation:

4 0
2 years ago
Help!!!
german

Answer:

625 cm3

Step-by-step explanation:

Formula V1 * P1 = V2 * P2

V1 = 450 cm3

P1 = 125 kPa

P2 = 90 kPa

V2 = ?

V2 = (V1 * P1) / P2

V2 = (450 cm3 * 125 kPa) / 90 kPa = 625 cm3

4 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
A parking space shaped like a parallelogram has a base of 17 feet and a height is 9 feet. A car parked in the space is 16 feet l
timama [110]
Ok, so we have to find areas and subtract

area=legnth times widht or base times height

parking space area=17 times 9=153
car=16 times 6=96


subtract
153-96=57
answer is 57 ft^2
4 0
3 years ago
Read 2 more answers
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