Answer:
ONE way in which population growth affected the development of technology in the period c. 1750-c. 1900 is described below in detailed explanation.
Explanation:
The Industrial Revolution transformed the standard and the way of living of the people because products are now manufactured by the new machines and technologies which are invented in the 1700s and 1900s that now make it possible to manufacture a mass production of goods in factories with help of new machines. this period also marked the period of rapid social and economic change in society.
Answer:
Explanation:
A) One Enlightenment philosopher’s idea that the American colonists used as a basis for revolution were John Locke's phrase "life, liberty, and pursuit of happiness," which is written in the Declaration of Independence. This phrase was written in the Declaration of Independence by Thomas Jefferson, who was inspired by John Locke.
B) One enlightenment philosophy outlined in the French Declaration of the Rights of Man and Citizen is the concept of individualism. The concepts in the Declaration come from the tenets of the Enlightenment, including individualism, the social contract as theorized by Jean-Jacques Rousseau, and the separation of powers espoused by Montesquieu.
C) In Latin America, Enlightenment thinkers like José Antonio de Alzate y Ramirez criticized William Robertson's ideas about indigenous history and the natural development of societies. Alzate y Ramirez rejected the rigid natural laws supposedly discovered by faraway philosophers. Instead, he said that local scholars had a better grasp of Amerindian society. He helped to lay intellectual foundations for Latin American independence movements in the nineteenth century.
Answer:
8.0 mi
Explanation:
Let's call your triangle ABC as in the diagram. We can use the SAS property of triangles and the Law of Sines.
1. Determine m∠B
m∠ B + 72° = 180°
m∠B = 108°
2. Determine b
By the Law of Sines,
b/sinB = c/sinC
b = c(sinB/sinC)
= 3 × (sin108°/sin17°)
= 3 × 0.951/0.292
= 9.76 mi
3. Calculate the area of ∆ABC
Area = ½ bc sinA = ½ × 9.76 × 3sin55° = ½ × 9.76 × 3 × 0.819 = 12.0 mi²
4. Calculate h
Area = ½ × base × height
12.0 mi² = ½ × 3 mi × h
h = 2 × 12.0 mi/3= 8.0 mi
The altitude of the plane is 8.0 mi.
Answer:
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Explanation:
