You can use the Pythagorean theorem for this problem.
a^2 + b^2 = c^2
a^2 + 5^2 = 10^2
a^2 + 25 = 100
a^2 = 75
a = 8.66
h = 8.7
Hope this helps =)
Answer:
C. 3x^2 + 2x + 1
Step-by-step explanation:
A. 12^2 - (4*3*12) = 0 (there's one solution.)
B. (-3)^2 - (4*3*-18) = 255 (there're 2 real solutions.)
D. 3^2 - (4*0*-3) = 9 (there're 2 real solutions.)
C. 2^2 - (4*3*1) = -18 ✅✅
if b^2 - 4ac = negative then we can say that there isn't any real solution for the equation.
6x+5=5x+8+2x
Add 2x to 5x
6x+5=7x+8
Subtract 6x from both sides
5=x+8
Subtract 8 from both sides
Final Answer: -3=x
And so no, -5 is not the solution to this equation.
Answer:
B
Step-by-step explanation:
For the tenths, if the hundredths digit is above 5, it rounds up. 7 is greater than 5, so it rounds the whole number to 0.6
For the hundredths, if the thousandths number is greater than 5, it rounds up. 8 is greater than 5, so it rounds the whole number to 0.58
Answer:
121 is a rational number, a perfect square.
Step-by-step explanation:
I know its a short answer, but I hope it helps.
