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Dahasolnce [82]
3 years ago
8

Match each system of equations with its number of solutions

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer:

Answer:

8x + 7y = 30 ( one solution)

8x - 7y = 2

-8x + 7y = -2 ( infinitely many solutions )

8x - 7y = 2

8x - 7y = 2

-8x + 7y = 2 ( zero solutions )

Step-by-step explanation:

Ostrovityanka [42]3 years ago
5 0

Answer:

8x + 7y = 30 ( one solution)

8x - 7y = 2

-8x + 7y = -2 ( infinitely many solutions )

8x - 7y = 2

8x - 7y = 2

-8x + 7y = 2 ( zero solutions )

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A map has a scale of 2cm=50 km.If two cities appear 10 cm meters apart, how many kilometers apart really are they?
ra1l [238]

Answer:

2 cm = 50 km

Find what the rate would be if 2 became 10 by dividing

10/2=5

multiply the 5 with the rate

5 x 50 = 250

250 km apart

hope this helps

Step-by-step explanation:

4 0
2 years ago
**HELP!**
mr_godi [17]
If two figures or lengths are similar, then the ratios of the corresponding lengths are equal.
Thus, 8/32 =5/x
          8x = 160
            x = 20 feet
Therefore, the length of the flag pole was 20 feet long
3 0
2 years ago
How many ways can a group of 8 students be selected from 9 students?
antoniya [11.8K]
9!/(8!*(9-8)!)=9
or just use a calculator and use the nCr function
7 0
3 years ago
Alex sold 330 candy bars, milk chocolate candy bars sold for $2 each and white chocolate candy bars sold for $3 each. Alex sold
Alinara [238K]

Answer:

<em>Alex sold 330 white chocolate bars</em>

Step-by-step explanation:

let the milk chocolate candy be x and the white chocolate candy be y. then

then 2x+3y=990----1)

x+y=330-----2)

from eq 2) ⇒ x=330-y---------3)

Putting eq 3 in eq 1

2(330-y) +3y=990

660-2y+3y=990

y=990-660=330-----------4)

Putting eq4 in eq1

2x+3(330)=990

2x+990=990

2x=990-990

2x=0

x=0---------------------------5)

4 0
3 years ago
Please I need help on this question, A line passes through (6,3), (8,4), and (n,-2). Find the value of n.
Vika [28.1K]

Answer:

n= -4

Step-by-step explanation:

First we have to find the equation of line which passes through (6,3) and (8,4).

Then we have to pass this line through the point (n , -2).

we know, equation of line passing through (x1,y1) and (x2,y2) is

\frac{x-x1}{x1-x2}=\frac{y-y1}{y1-y2}

So, the equation of line passing through (6,3) and (8,4) is

\frac{x-6}{6-8}=\frac{y-3}{3-4}

or, \frac{x-6}{-2} =\frac{y-3}{-1}

multiplying both sides by  -2

x-6=2(y-3)

or, x-6=2y-6

or, x-2y=6-6

or, x-2y=0


Now, we have to pass this line through  (n,-2)

So, using the point in the line, that is using  x=n  , y=-2

we get

n-2(-2)=0

or, n+4=0

or, n=-4

6 0
3 years ago
Read 2 more answers
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