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Dahasolnce [82]
3 years ago
8

Match each system of equations with its number of solutions

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer:

Answer:

8x + 7y = 30 ( one solution)

8x - 7y = 2

-8x + 7y = -2 ( infinitely many solutions )

8x - 7y = 2

8x - 7y = 2

-8x + 7y = 2 ( zero solutions )

Step-by-step explanation:

Ostrovityanka [42]3 years ago
5 0

Answer:

8x + 7y = 30 ( one solution)

8x - 7y = 2

-8x + 7y = -2 ( infinitely many solutions )

8x - 7y = 2

8x - 7y = 2

-8x + 7y = 2 ( zero solutions )

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8473; to the nearest thousand
ehidna [41]

Answer:8000

Step-by-step explanation:It is 8000 because I’m the hundreds place there is a 4, if there is anything less than a 5 or less you round down, 5 or more you round up.

8 0
3 years ago
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Why is the lady’s shadow in the picture not a rigid transformation?
Eva8 [605]

Answer:

The shadow is not the same image as the lady

Step-by-step explanation:

Had it in a test got it right

5 0
3 years ago
A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t
aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}

Knowing that t_{0.99,15} = 2.602:

IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516

IC[\mu ; 98\%] = [71.387 ; 126,416]

Note that 102.8 \in [71.384 ; 126.416] so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.

7 0
3 years ago
In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each
Rudiy27

Answer:

N(t) = 972(1.015)^{t}

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

N(t) = N(0)(1+r)^{t}

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that N(0) = 972

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that r = 0.015

Then

N(t) = N(0)(1+r)^{t}

N(t) = 972(1+0.015)^{t}

N(t) = 972(1.015)^{t}

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

N(t) = 972(1.015)^{t}

N(12) = 972(1.015)^{12}

N(12) = 1162

The number of students enrolled in 2014 is 1162.

7 0
3 years ago
Shawnee is putting $3,500 into an account earning 4.85% interest compounded quarterly. She estimates that it will take just over
Murljashka [212]
A=3,500×(1+0.0485÷4)^(4×11)
A=5,947.99

6000=3500(1+0.0485/4)^4t
Solve for t to know the time needed to reach 6000
Time=11.2
So the time needed is 11 years and 2 months
8 0
3 years ago
Read 2 more answers
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