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Vlad1618 [11]
3 years ago
8

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

rmelon crop (in dollars). What is the margin of error (in dollars)
Mathematics
1 answer:
Anon25 [30]3 years ago
7 0

Answer:

The margin of error (E)  =0.49

Step-by-step explanation:

Given,

 mean \bar{x}=6.88

 standard deviation \sigma=1.90

 sample size n=41

90\% \quad \text{confidence interval}

Critical value =\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]  

                                                =1-0.90

                                        \Rightarrow \alpha=0.1

Critical value =\frac{z_{0.1}}{2}

                      =z_{0.05}

                      =1.645

The margin of error (E)  =\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }

                                       =1.645\times\frac{1.90}{\sqrt{41} }

                                       =0.49

Hence, The margin of error (E) =0.49

Complete question is attached in below.

                     

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