Given:
Cost of two donuts and three cookies = $3.30
Cost of five donuts and two cookies = $4.95
To find:
The cost of each donut.
Solution:
Let x be the cost of each donut and y be the cost of each cookie.
Cost of two donuts and three cookies = $3.30
...(i)
Cost of five donuts and two cookies = $4.95
...(ii)
Multiply equation (i) by 2.
...(iii)
Multiply equation (ii) by 3.
...(iv)
Subtracting (iii) from (iv), we get
Divide both sides by 11.
Therefore, the cost of each donut is $0.75.
Yes you can because you just can
Answer:
H₀: µ ≤ $8,500; H₁: µ > $8,500
z= +1.645
Step-by-step explanation:
From the given problem As average cost of tuition and room and board at a small private liberal is less than the financial administrator As hypothesis is true.
As standard deviation is $ 1,200
α = 0.05
H₀: µ ≤ $8,500
if the null hypothesis is true then value for critical z is +1.645.
Step-by-step explanation:
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Answer: 21 :D
Step-by-step explanation:
