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olga55 [171]
2 years ago
11

Hey can anyone help me with my math assignment its the last question on my profile thanks!​

Mathematics
2 answers:
timama [110]2 years ago
7 0
Ok I’ll Take a look Try to help you
Luda [366]2 years ago
5 0
Sure I’ll take a look
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The sides of a rectangle are in the ratio 5 : 4. If the perimeter of the rectangle is 360 cm , find its area
djverab [1.8K]

Answer:

Step-by-step explanation:

let, the length is z

thus the ratio will be 5z : 4z

perimeter = 2 (a + b)

360 = 2 ( 5z + 4z )

180 = 9z

z = 20 cm

length = 100 cm and width = 80cm

area = length * width

area = 100*80

area = 8000cm²

4 0
2 years ago
1 what is sum of the interior angles of ABCD what is the sum of the exterior angles of CHFE 3 which sides are parallel to CE 4 w
expeople1 [14]

Given that ABCD is a parallelogram, the sum of its interior angles is:
360°

<h3>What is a parallelogram?</h3>

A parallelogram is a rectilinear two-dimensional figure with four sides whose opposite sides are parallel. See the image attached.

<h3>What is the sum of the exterior angles of CHFE?</h3>

The sum of the exterior angles of any Triangle or any polygon is 360°. Hence, the sum of the exterior angles of CHFE (a polygon) is 360°.

<h3>Which sides are parallel to CE?</h3>

The sides that are parallel to CE are:

FH

AD and

<h3>IJ.

Which side is perpendicular to CE?</h3>

The side that are perpendicular to CE is side side HH, hence we can state that:

CE ⊥ EH, because both lines intersect each other at right angles.

<h3>What is the sum of ∠C and ∠H?</h3>

Because the sum of angles in a triangle is 180° and we already have ∠CEH to be equal to ∠90° hence,

∠C + ∠H? = 180° - 90°

= 90°

<h3>What is the measure of the exterior angles of a Regular Pentagon?</h3>

The measure of the exterior angles of a regular pentagon is 72°

Learn more about Parallelograms at:
brainly.com/question/970600
#SPJ1

5 0
2 years ago
Sin^2x + sin2x +2cox^2x = 2
Effectus [21]

Answer:

Step-by-step explanation:

sin^2 \ x + sin ^2 \ x + 2cos^ 2\ x = 2\\\\2sin^2 \ x  + 2 cos^2 \ x = 2\\\\2 ( sin^2 \ x + cos^2 \ x ) = 2 \\\\2 \times 1 = 2 \\\\2 = 2 \\\\LHS = RHS \\\\Hence \ proved.

5 0
2 years ago
How do you solve this?
Kobotan [32]

Answer:

Well one do the square root of 16

3 0
2 years ago
Read 2 more answers
2 + 2<br> please tell me I am clueless
dezoksy [38]

Answer:

22

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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