Can someone PLEASE help me :((

Marianne has 5/8 package of peas. She cooks 2/3 of those peas for 5 people. If each person is served an equal amount, what fract

creativ13 [48]

5/8 and 2/3 so...
8 times 3 is 24 so now put your fraction over twenty four
15/24=5/8
15/24 so fifteen out of twenty fourths of the package is what she has. She takes ten out of the fifteenths because fifteen divided by three is five then multiply by two is ten. Then divide by five and you get two.
15/24. 10-> 15/24 cause... 15 divided by 3 ( from the two thirds she cooked) is 5 then * by 2... 5*2=10

5 0

3 years ago

If using the method of completing the square to solve the quadratic

In-s [12.5K]

Answer:

100

Step-by-step explanation:

20/2= 10 and 10 squared is 100 but you have to move the -6 to the opposite side

4 0

3 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago

I need help with this please

Ierofanga [76]

C is the correct answer

we should find the area of the square and then divide it by 24.
(360/15=24)

$6 \times 6 \times \pi \times \frac{1}{24} = 36 \times \pi \times \frac{1}{24} \\ = 113.04 \times \frac{1}{24} = 4.71$

good luck

8 0

3 years ago

Read 2 more answers

Can someone help me find the slope?

kipiarov [429]

Answer:

Undefined

Step-by-step explanation:

First, take 2 points from the table given, then you use the equation y2-y1/x2-x1 to find your slope. So, if I take the coordinates (7,1) and (7,2) and plug them into my equation, I would get 2-1/7-7. If you solve this equation, you will end up wil 1/0. Now, if you have something like this as your answer, you can not find your slope. There can not be a slope because the zero is at the bottom, making this "Undefined".

7 0

2 years ago