Find an equation of the line that passes through the pair of points (-5, -9) and (2,-7)

Mathematics

1 answer:

vladimir1956 [14]2 years ago

4 0

Answer:

y=0.3x - 7.6

Step-by-step explanation:

line: y=ax+b

a= Δy ÷ Δx

a= (-9 + 7) ÷ (-5 - 2)

a= -2 ÷ -7 = approximately 0.3

y=0.3x + b

Now you can fill in one of the points to find b (or both to make sure you got the answer right).

0.3 × 2 + b = -7

0.6 + b = -7

b = -7 - 0.6 = approximately -7.6

So: an equation of the line that passes through this pair of points is y=0.3x - 7.6

On a test, i would write as many decimals as possible if not said not to, to get the most exact answer. Also remember to keep calculating with the number on your calculator and not to round them off for the most exact answer.

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If i make 10 fruit baskets and want to sell them for $35 each 10=35x what's my answer

ivolga24 [154]

You made a teeny mistake! Instead of 10=35x, it should be (35)(10)=x; so in this case, you would make $350 from 10 fruit baskets.

8 0

2 years ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$