Step-by-step explanation:
x = -2 and x = -5
x + 2 = 0 and x + 5 = 0
(x + 2)(x + 5) = 0
x² + 5x + 2x + 10 = 0
x² + 7x + 10 = 0
Option → B
Answer:
The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.
<em />
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>
We can model this as a binomial random variable, with p=0.57 and n=14.

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:




Let
x-------> bags of <span>popcorn
</span>y-------> bags of hotdogs
we know that
2.50x+3y=200-------> equation 1
x=2y--------> equation 2
substitute 2 in 1
2.50*[2y]+3y=200--------> 5y+3y=200------> 8y=200-----> y=200/8
y=25
x=2y-----> x=2*25-----> x=50
the answer is
50 bags of popcorn
25 bags of hotdogs<span />
Answer:
Monday he walked
Wednesday he walked
Friday he walked
Step-by-step explanation:
Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.
distances are
that are 0.75, 0.25 and 0.17 respectively.
Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.
∴ Less distance travelled is
which is on friday and then
on monday.
Rest distance which is
on wednesday.
Hence, Monday he walked
Wednesday he walked
Friday he walked