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zhenek [66]
3 years ago
8

6x^2+x-12 in factored form

Mathematics
1 answer:
pychu [463]3 years ago
5 0
6x²+x-12

the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)

two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term

6x²+9x-8x-12

now we look for whats common between the first two numbers and divide them out

6x²+9x = 3x(2x+3)

now we do the same with the last two numbers

-8x-12 = -4(2x+3)

notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside

once we do that you should get an answer of 

(3x-4)(2x+3)

hope this helped!


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what is the result of dividing 48a^3 + 32a^2 + 16a by 4a? A. 12a^2 + 8a + 4 B. 12a^2 + 4a + 8 C. 12a + 8 D. 12a^2 + 4a + 4 Simpl
lora16 [44]

Answer:

1. A. 12a^2 + 8a + 4

2. C. 4xy+16x-4y^2-16y

3. C. 64q^6r^8s^4

4. A. -4x^4y^6

Step-by-step explanation:

48a^3 + 32a^2 + 16a / 4a = (48a^3) / 4a + (32a^2) / 4a + (16a) / 4a = 12a^2 + 8a + 4.

So, the answer is A. 12a^2 + 8a + 4.

(2x-2y)(2y+8) = 4xy - 4y^2 + 16x -  16y.

So, the answer is C. 4xy+16x-4y^2-16y.

(-8q^3 * r^4 * s^2)^2 = (-8)^2 * q^6 * r^8 * s^4 = 64q^6r^8s^4.

So, the answer is C. 64q^6r^8s^4.

-12x^8y^8 / 3x^4y^2 = (-12 / 3) * (x^(8 - 4)) * (y^(8 - 2)) = -4x^4y^6.

So, the answer is A. -4x^4y^6.

Hope this helps!

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Step-by-step explanation:

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