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2 years ago

Help pls ;) 9 points :0

Mathematics

1 answer:

zavuch27 [327]2 years ago

6 0

I believe it’s b- it might not be correct I believe

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A pet store owner surveys his customers about the number of pets they own. The results are below:

finlep [7]

For percentages, use a pie graph.

5 0

2 years ago

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Which is the equation of the line shown in the graph?

elixir [45]

I think the right answer is A

6 0

2 years ago

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Find the distance between the points A (13, 2) and B (7, 10).

Aliun [14]

Answer:

Step-by-step explanation:

d = 10

For:

(X1, Y1) = (13, 2)

(X2, Y2) = (7, 10)

Distance Equation Solution:

d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√

d=(−6)2+(8)2−−−−−−−−−−√

d=36+64−−−−−−√

d=1–√00

d=10

4 0

2 years ago

carlos and Jacob each improve their yards by planting daylilies and ivy. They bought their supplies from the same stores. Carlos

34kurt

Answer:

Cost of each daylilies = $3

Cost of each ivy pot = $3

Step-by-step explanation:

Given:

Cost of 4 daylilies and 4 ivy = $24

Cost of 4 daylilies and 8 ivy = $36

Find:

Cost of each daylilies

Cost of each ivy pot

Computation:

Assume;

Cost of each daylilies = a

Cost of each ivy pot = b

So,

4a + 4b = 24....... eq 1

4a + 8b = 36 ....... eq 2

Eq2 - Eq1

8b - 4b = 36 - 24

4b = 12

b = 3

So,

Cost of each ivy pot = $3

4a + 4b = 24

4a + 4(3) = 24

4a + 12

a = 3

Cost of each daylilies = $3

6 0

3 years ago

The lengths of a particular snake are approximately normally distributed with a given mean mu = 15 in. and standard deviation si

Helga [31]

The percentage of the snakes is longer than 16.6 in. with a mean of 15 in. and a standard deviation of 0.8 in. is 2.275%.

<h3>What is a normal distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in.

Then the percentage of the snakes is longer than 16.6 in. will be

$z = \dfrac{ x - \mu }{ \sigma }\\\\z = \dfrac{16.6-15}{0.8}\\\\z = 2$

Then we have

$\rm P(x > 16.6) = P(z > 2) = 0.02275 \ or \ 2.275 \%$

More about the normal distribution link is given below.

brainly.com/question/12421652

6 0

2 years ago