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3 years ago

A community is considering raising funds to pay for improvements to the community swimming pool. To measure the

Mathematics

1 answer:

dezoksy [38]3 years ago

6 0

Answer:

All residents of the community

Step-by-step explanation:

Not sure if this is fully correct but the 2nd and 3rd option is wrong (Edg 2021)

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Find 5g(x)-f(x) given f(x)=9x^2+7x and g(x)=2-x

givi [52]

Answer:

- 9x² - 12x + 10

Step-by-step explanation:

5g(x) - f(x)

= 5(2 - x) - (9x² + 7x) ← distribute both parenthesis

= 10 - 5x - 9x² - 7x ← collect like terms

= - 9x² - 12x + 10

4 0

3 years ago

The following section is a statement from the rental agreement at a local auto rental agency. “Upon checkout, the fuel level of

marishachu [46]

Answer:

a. Refuel the vehicle before the Renter drives it away.

Step-by-step explanation:

The rental agency representative must check the fuel level, mark it on the check-out sheet and give a copy of the check-out sheet to the renter. He or she does not, however, need to refuel the vehicle for the renter.

6 0

3 years ago

Read 2 more answers

You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

brilliants [131]

Answer:

Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$