Solve: sin2x cosx + cos 2x sin x = √3/2 for 0

Mathematics

1 answer:

artcher [175]2 years ago

5 0

Answer:

$x=\frac{\pi }{9}+\frac{2k\pi }{3} ,\frac{2\pi }{9}+\frac{2k\pi }{3}$

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$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
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b=opposite\\
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