This is a question that can be solved with Pythagorean Theorem since it is a right triangle. The longest side, 29, is the hypotenuse and the sides 21 and x are the legs. So, the Pythagorean Theorem states,

$c^{2}= a^{2}+ b^{2}$

Where,

c is the Hypotenuse, a and b are the legs. Putting the respective values gives us,

$(29)^{2}= (21)^{2} +x^{2} \\841=441+x^{2} \\400=x^{2} \\20=x$

So, 20 is the side length of x.

ANSWER: 20

5 0

3 years ago

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The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

Maurinko [17]

The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
 area = 19.3138746047 

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / 1.65684 
area = 173.824871442 

 173.824871442 / 19.3138746047 = 9

So, the area would be 9 times larger.

ALSO, looking at the formula
n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

5 0

3 years ago