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3 years ago

6

Santa’s sleigh has a Clausometer. The highest measure is 100 percent. If the Clausometer measured at 45. What would this number

be represented as a decimal?

1 answer:

Step2247 [10]3 years ago

5 0

Answer:

0.45

Step-by-step explanation:

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Dafna1 [17]

3 + 7 > 10 - 2
10 > 8...correct

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3 years ago

What shape is created by a cross-section of a triangular prism cut perpendicular to the bases?

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Sean and Greg share a 24-ounce bucket of clay. By the end of the week, Sean has used 3 8 of the bucket, and Greg has used 1 4 of

kozerog [31]

Answer:

9

Step-by-step explanation:

Sean and Greg share a 24-ounce bucket of clay

Sean uses 3/8 of the bucket

= 3/8 ×24

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Greg uses 1/4 if the bucket

= 1/4 ×24

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3 years ago

Find the sine ratio of angle Θ. Hint—Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no sp

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Answer:

sinΘ = $\frac{12}{13}$

Step-by-step explanation:

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2 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago