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Marysya12 [62]
3 years ago
6

Solve: 4(-6) = -9(5) = -1.5(-7) =

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

5

Step-by-step explanation:

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What is the solution of the system? y=145-5x and 0.1+0.5x=14.5
Jobisdone [24]
145−5x(0.1)+0.5=14.5
Step 1: Simplify both sides of the equation.
145−5x(0.1)+0.5=14.5
145+−0.5x+0.5=14.5
(−0.5x)+(145+0.5)=14.5(Combine Like Terms)
−0.5x+145.5=14.5
−0.5x+145.5=14.5
Step 2: Subtract 145.5 from both sides.
−0.5x+145.5−145.5=14.5−145.5
−0.5x=−131
Step 3: Divide both sides by -0.5.
−0.5x
−0.5
=
−131
−0.5
x=262
Answer:
x=262

8 0
3 years ago
Which of the below options shows the correct format for scientific
aev [14]

(b) 1

(c) 34.765 x 10^-4

(d)  2.56 x 10^2

<u>Explanation:</u>

Scientific notation is a way of expressing numbers that are too big or too small to be conveniently written in decimal form.

In this case, the scientific notation of 00.0602 will be 6 X 10⁻⁴

1 , 34.765 x 10⁻⁴  and 2.56 x 10² are already in scientific notation form.

7 0
3 years ago
In a thunderstorm, the wind velocity in meters per second can be described by the function v(p) = 5.7 √998 - p, where p is the a
nataly862011 [7]

Answer:

923.1927 millibars

Step-by-step explanation:

The wind velocity is given by the function:

v(p)=5.7\sqrt{(998-p}

#We make p the subject of the formula:

v(p)=5.7\sqrt{(998-p}\\\\v=5.7\sqrt{(998-p}\\\\\frac{v}{5.7}=\sqrt{(998-p}\\\\\frac{v^2}{5.7^2}=998-p\\\\p=998-\frac{v^2}{5.7^2}

#Substitute the given values in the function above to solve for p;

p=998-\frac{v^2}{5.7^2}\\\\=998-\frac{49.3^2}{5.7^2}\\\\=923.1927\ millibars

Hence, the air pressure is 923.1927 millibars.

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